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Status: Waiting for your answers.

Problem: Solve for the variable. Check a value if it is extraneous.   √ y + 32  = y + 12   y + 32 = ( y + )2   y + 32 = y2 + y +   0 = y2 + y +   0 = ( y + )( y + )   y1 =     y2 = extraneous   extraneous