Solving Radical Equations 2 with Help
View the Lesson | MATHguide homepage Updated June 22nd, 2023


Status: Waiting for your answers.





Problem: Solve for the variable. Check a value if it is extraneous.
 
b + 6  = b + 4
 
b + 6 = ( b + )2
 
b + 6 = b2 + b +
 
0 = b2 + b +
 
0 = ( b + )( b + )
 
b1 =     b2 =
extraneous   extraneous