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Status: Waiting for your answers.

Problem: Solve for the variable. Check a value if it is extraneous.   √ k + 22  = k + 10   k + 22 = ( k + )2   k + 22 = k2 + k +   0 = k2 + k +   0 = ( k + )( k + )   k1 =     k2 = extraneous   extraneous