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Status: Waiting for your answers.

Problem: Solve for the variable. Check a value if it is extraneous.   √ b + 5  = b - 1   b + 5 = ( b + )2   b + 5 = b2 + b +   0 = b2 + b +   0 = ( b + )( b + )   b1 =     b2 = extraneous   extraneous