Solving Radical Equations 2 with Help
View the Lesson | MATHguide homepage Updated June 22nd, 2023

Status: Waiting for your answers.





Problem: Solve for the variable. Check a value if it is extraneous.
 
√ y + 12  = y + 10
 
y + 12 = ( y + )2
 
y + 12 = y2 + y +
 
0 = y2 + y +
 
0 = ( y + )( y + )
 
y1 =     y2 =
extraneous   extraneous