Waiting for your responses... Answer the following chemistry problem. Report the volume to the nearest milliliter of carbonic acid. How many milliliters of 45% carbonic acid must be mixed with how many milliliters of 85% carbonic acid to make 520 milliliters of a 73% carbonic acid solution? The number of milliliters of 45% carbonic acid needed is milliliters. The number of milliliters of 85% carbonic acid needed is milliliters.
How many milliliters of 45% carbonic acid must be mixed with how many milliliters of 85% carbonic acid to make 520 milliliters of a 73% carbonic acid solution?