Waiting for your responses... Answer the following chemistry problem. Report the volume to the nearest milliliter of carbonic acid. How many milliliters of 30% carbonic acid must be mixed with how many milliliters of 55% carbonic acid to make 770 milliliters of a 47% carbonic acid solution? The number of milliliters of 30% carbonic acid needed is milliliters. The number of milliliters of 55% carbonic acid needed is milliliters.
How many milliliters of 30% carbonic acid must be mixed with how many milliliters of 55% carbonic acid to make 770 milliliters of a 47% carbonic acid solution?