Status: Waiting for your answers. Problem: A painting will appreciate in value at a 6.6% annual rate. Currently, it is worth $280. When will its value be $840? Calculate the time (to the nearest tenth in years) by using this formula.A = a(1 + r)^{t} Solution: = ( 1 + )^{t} = ( )^{t} = ( )^{t} log = t ≈ t

Calculate the time (to the nearest tenth in years) by using this formula.