Solving Radical Equations 2 with Help
View the Lesson | MATHguide homepage Updated November 11th, 2017


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Problem: Solve for the variable. Check a value if it is extraneous.
 
x + 3  = x - 3
 
x + 3 = ( x + )2
 
x + 3 = x2 + x +
 
0 = x2 + x +
 
0 = ( x + )( x + )
 
x1 =     x2 =
extraneous   extraneous