Solving Radical Equations 2 with Help
View the Lesson | MATHguide homepage Updated June 22nd, 2023


Status: Waiting for your answers.





Problem: Solve for the variable. Check a value if it is extraneous.
 
j + 25  = j + 13
 
j + 25 = ( j + )2
 
j + 25 = j2 + j +
 
0 = j2 + j +
 
0 = ( j + )( j + )
 
j1 =     j2 =
extraneous   extraneous