Solving Radical Equations 2 with Help
View the Lesson | MATHguide homepage Updated June 22nd, 2023

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Problem: Solve for the variable. Check a value if it is extraneous.
 
√ x + 55  = x - 1
 
x + 55 = ( x + )2
 
x + 55 = x2 + x +
 
0 = x2 + x +
 
0 = ( x + )( x + )
 
x1 =     x2 =
extraneous   extraneous