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Answer the following chemistry problem. Report the volume to the nearest milliliter of carbonic acid.

How many milliliters of 60% carbonic acid must be mixed with how many milliliters of 45% carbonic acid to make 550 milliliters of a 51% carbonic acid solution?


The number of milliliters of 60% carbonic acid needed is milliliters.
The number of milliliters of 45% carbonic acid needed is milliliters.