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Answer the following chemistry problem. Report the volume to the nearest milliliter of sulfuric acid.

How many milliliters of 80% sulfuric acid must be mixed with how many milliliters of 35% sulfuric acid to make 720 milliliters of a 41% sulfuric acid solution?

The number of milliliters of 80% sulfuric acid needed is milliliters.

The number of milliliters of 35% sulfuric acid needed is milliliters.