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Answer the following chemistry problem. Report the volume to the nearest milliliter of carbonic acid.

How many milliliters of 90% carbonic acid must be mixed with how many milliliters of 55% carbonic acid to make 640 milliliters of a 80% carbonic acid solution?

The number of milliliters of 90% carbonic acid needed is milliliters.

The number of milliliters of 55% carbonic acid needed is milliliters.