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Answer the following chemistry problem. Report the volume to the nearest milliliter of sulfuric acid.

How many milliliters of 35% sulfuric acid must be mixed with how many milliliters of 15% sulfuric acid to make 530 milliliters of a 23% sulfuric acid solution?


The number of milliliters of 35% sulfuric acid needed is milliliters.
The number of milliliters of 15% sulfuric acid needed is milliliters.